+don Khan, thanks for checking out our tutorial.
Both are ways to create a String object.
String s = "hello";
This is literal String. If there is "hello" string present in poll, it doesn't create the new String "hello". It will pick it form the pool and refer it,
otherwise it will create the String "hello". But, in String s = new String("hello"); first the literal hello pick from the pool if it's present and passed to the overloaded String class constructor. Otherwise, it will create and pass to the overloaded constructor of String String(String s) and create the new string object through new String ("hello");

Hope this helps. Cheers!

Hello @RS-so7ke! Excellent question! The difference lies in how the Java Memory Model handles these two.

When we say `String s = "hello";`, we're actually creating a string literal. In this case, Java checks the String Constant Pool first and if it finds an identical string already present there, it assigns the same reference to the new variable; it doesn't create a new object in this case.

On the other hand, `String s = new String("hello");` always results in a new object on the heap irrespective of whether a similar string exists or not in the String Constant Pool. So, it always consumes extra memory.

This different behaviour influences a lot of operational nuances and is important while dealing with string manipulations, comparisons etc. Keep learning! You can always reach out here if you have more questions. 😊

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Hey Vijaya,
All the messages are getting printed because of Constructor Chaining which means calling one constructor from another constructor with respect to current object. If you see the code, the 1st line of the default constructor is this(x:0) which is invoking the next constructor. Similarly, rest of the constructors are also invoked. Hope this clears your doubt."

Hope this helps!

Hello @vijayalakshmi6028, thank you for bringing up your question. Let's clarify this matter. You are referring to the instance where an object is created with no arguments such as with new A(). In this case, indeed, only the method or constructor A() would be executed. Therefore, the output in this case would rightfully be "Hi". But remember, in Java, constructors are special methods invoked when an object is created and they share the name with the class. If your code doesn't explicitly call a constructor, Java will implicitly call the no-argument constructor for you. If there are parameters in the constructor, like in A(int x), and we write new A(), it would call the no-argument constructor, not A(int x). Hope that helps. Please feel free to drop more questions if you have any. Happy learning!

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